2x^2+21x+402=0

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Solution for 2x^2+21x+402=0 equation: 



2x^2+21x+402=0

a = 2; b = 21; c = +402;
Δ = b2-4ac
Δ = 212-4·2·402
Δ = -2775
Delta is less than zero, so there is no solution for the equation

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